[php] notice

Pozdravljeni,

dobim tak notice v php-ju.

A PHP Error was encountered

Severity: Notice

Message: Only variable references should be returned by reference

Filename: core/Common.php

Line Number: 243

Source:

function &getconfig($replace = array())

{

static $config;

if (isset($config))

{

return $config[0];

}

// Is the config file in the environment folder?

if ( ! defined('ENVIRONMENT') OR ! fileexists($filepath = APPPATH.'config/'.ENVIRONMENT.'/config'.EXT))

{

$filepath = APPPATH.'config/config'.EXT;

}

// Fetch the config file

if ( ! fileexists($filepath))

{

exit('The configuration file does not exist.');

}

require($filepath);

// Does the $config array exist in the file?

if ( ! isset($config) OR ! isarray($config))

{

exit('Your config file does not appear to be formatted correctly.');

}

// Are any values being dynamically replaced?

if (count($replace) > 0)

{

foreach ($replace as $key => $val)

{

if (isset($config[$key]))

{

$config[$key] = $val;

}

}

}

return $config[0] =& $config;

}

kako bi se rešil tega notica? je zgolj notice, vendar je napaka v vrstici:

return $_config[0] =& $config;

Hvala za vašo pomoč in trud.

Stara Joomla?

Si preveril Google, kot je recimo: http://stackoverflow.com/questions/28348879/only-variable-references-should-be-returned-by-reference-codeigniter

ni joomla, codeigniter application.

php.programer:

ni joomla, codeigniter application.

ideja je ista, si preveril?

sem dela. hvala.